Clippers forward Kawhi Leonard and Bucks forward/center Bobby Portis have been named the NBA’s players of the week, the league announced today (via Twitter).
Leonard averaged 25.7 points, 10.0 rebounds and 4.7 assists on .491/.389/.842 shooting in leading the Clippers to a 3-0 record last week. They secured the No. 5 seed in the Western Conference playoffs and will face Phoenix in the first round.
In 52 games this season, the two-time Finals MVP averaged 23.8 points, 6.5 rebounds, 3.9 assists and 1.4 steals on .512/.416/.871 shooting. Leonard is under contract at $45.6MM in 2023/24 and holds a $48.8MM player option for ’24/25.
Portis, the East’s winner, averaged 20.0 points and 12.3 boards on .447/.591/.636 shooting in three games last week. The Bucks went 2-1 in those contests and 2-2 overall last week, resting some key players as they locked up the NBA’s top overall seed for the playoffs.
The 28-year-old averaged 14.1 points and a career-high 9.6 rebounds on .496/.370/.768 shooting in 70 games this season, primarily off the bench (22 starts, 26.0 minutes). The veteran big man should get some votes for Sixth Man of the Year following his strong regular season. Portis is under contract through at least ’24/25 with a player option for ’25/26.
According to the NBA (Twitter link), the other nominees in the West were Stephen Curry, Anthony Edwards, Brandon Ingram and LeBron James, while Jimmy Butler, Portis’ teammate Jrue Holiday, Immanuel Quickley and Pascal Siakam were nominated in the East.