Jrue Holiday Wins Teammate Of The Year Award

Pelicans guard Jrue Holiday has been named the winner of the NBA’s 2019/20 Twyman-Stokes Teammate of the Year Award, the league announced today in a press release.

The award, which was voted on by more than 250 NBA players, recognizes the player deemed to be the best teammate based on “selfless play, on- and off-court leadership as a mentor and role model to other NBA players, and commitment and dedication to team.” Mike Conley, Jamal Crawford, Dirk Nowitzki, and Vince Carter have each won the award during the past few years.

One of 12 players nominated by a panel of league executives for this year’s award, Holiday was the leading vote-getter among those dozen players, receiving 53 of 267 possible first-place votes. He beat out runners-up Tobias Harris and Kyle Korver for the honor. The full voting results can be found right here.

Holiday averaged 19.1 PPG, 6.7 APG, 4.8 RPG, and 1.6 SPG with a .455/.353/.709 shooting line in 61 games (34.7 MPG) for the Pelicans in 2019/20. He announced in July that he would be putting his game checks from the summer restart toward the Jrue and Lauren Social Justice Impact Fund, a fund dedicated to helping communities in New Orleans, Indianapolis, and the Los Angeles area.

New Orleans’ front office will face a decision on Holiday’s future within the next year or so. He holds a player option for the 2021/22 season, meaning he may be entering a contract year in ’20/21. The Pelicans will have to determine whether it makes sense to consider trading the veteran guard in advance of his free agency or whether they’re committed to trying to keep him long-term.

Photo courtesy of USA Today Sports Images.